(2z^2-3z-4)-(z^2-5)=x

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Solution for (2z^2-3z-4)-(z^2-5)=x equation:


Simplifying
(2z2 + -3z + -4) + -1(z2 + -5) = x

Reorder the terms:
(-4 + -3z + 2z2) + -1(z2 + -5) = x

Remove parenthesis around (-4 + -3z + 2z2)
-4 + -3z + 2z2 + -1(z2 + -5) = x

Reorder the terms:
-4 + -3z + 2z2 + -1(-5 + z2) = x
-4 + -3z + 2z2 + (-5 * -1 + z2 * -1) = x
-4 + -3z + 2z2 + (5 + -1z2) = x

Reorder the terms:
-4 + 5 + -3z + 2z2 + -1z2 = x

Combine like terms: -4 + 5 = 1
1 + -3z + 2z2 + -1z2 = x

Combine like terms: 2z2 + -1z2 = 1z2
1 + -3z + 1z2 = x

Solving
1 + -3z + 1z2 = x

Solving for variable 'z'.

Reorder the terms:
1 + -1x + -3z + 1z2 = x + -1x

Combine like terms: x + -1x = 0
1 + -1x + -3z + 1z2 = 0

The solution to this equation could not be determined.

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